14012143401 has 8 divisors (see below), whose sum is σ = 18729450144. Its totient is φ = 9318132800.

The previous prime is 14012143367. The next prime is 14012143433. The reversal of 14012143401 is 10434121041.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 14012143401 - 2⁷ = 14012143273 is a prime.

It is a super-3 number, since 3×14012143401³ (a number of 31 digits) contains 333 as substring.

It is not an unprimeable number, because it can be changed into a prime (14012143441) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5822631 + ... + 5825036.

It is an arithmetic number, because the mean of its divisors is an integer number (2341181268).

Almost surely, 2^14012143401 is an apocalyptic number.

It is an amenable number.

14012143401 is a deficient number, since it is larger than the sum of its proper divisors (4717306743).

14012143401 is a wasteful number, since it uses less digits than its factorization.

14012143401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11648071.

The product of its (nonzero) digits is 384, while the sum is 21.

Adding to 14012143401 its reverse (10434121041), we get a palindrome (24446264442).

The spelling of 14012143401 in words is "fourteen billion, twelve million, one hundred forty-three thousand, four hundred one".