Base | Representation |
---|---|
bin | 11010000110011000… |
… | …10110001110011001 |
3 | 1100011112110010110022 |
4 | 31003030112032121 |
5 | 212144111241441 |
6 | 10234230200225 |
7 | 1004143560245 |
oct | 150314261631 |
9 | 40145403408 |
10 | 14012212121 |
11 | 5a4058a3a6 |
12 | 28707b3075 |
13 | 1423cc659b |
14 | 96cd75425 |
15 | 57024684b |
hex | 343316399 |
14012212121 has 2 divisors, whose sum is σ = 14012212122. Its totient is φ = 14012212120.
The previous prime is 14012212079. The next prime is 14012212129. The reversal of 14012212121 is 12121221041.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 14010036496 + 2175625 = 118364^2 + 1475^2 .
It is an emirp because it is prime and its reverse (12121221041) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 14012212121 - 26 = 14012212057 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 14012212121.
It is not a weakly prime, because it can be changed into another prime (14012212129) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7006106060 + 7006106061.
It is an arithmetic number, because the mean of its divisors is an integer number (7006106061).
Almost surely, 214012212121 is an apocalyptic number.
It is an amenable number.
14012212121 is a deficient number, since it is larger than the sum of its proper divisors (1).
14012212121 is an equidigital number, since it uses as much as digits as its factorization.
14012212121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 64, while the sum is 17.
Adding to 14012212121 its reverse (12121221041), we get a palindrome (26133433162).
The spelling of 14012212121 in words is "fourteen billion, twelve million, two hundred twelve thousand, one hundred twenty-one".
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