Base | Representation |
---|---|
bin | 10100011000111111010… |
… | …010111010110001110011 |
3 | 11221221210112000100121111 |
4 | 110120333102322301303 |
5 | 140424200120344301 |
6 | 2551413454334151 |
7 | 203143366132663 |
oct | 24307722726163 |
9 | 4857715010544 |
10 | 1401221262451 |
11 | 4a02889668aa |
12 | 1a76961ba357 |
13 | a219993428a |
14 | 4bb688b21a3 |
15 | 266b049a551 |
hex | 1463f4bac73 |
1401221262451 has 2 divisors, whose sum is σ = 1401221262452. Its totient is φ = 1401221262450.
The previous prime is 1401221262439. The next prime is 1401221262517. The reversal of 1401221262451 is 1542621221041.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1401221262451 is a prime.
It is not a weakly prime, because it can be changed into another prime (1401221262401) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 700610631225 + 700610631226.
It is an arithmetic number, because the mean of its divisors is an integer number (700610631226).
Almost surely, 21401221262451 is an apocalyptic number.
1401221262451 is a deficient number, since it is larger than the sum of its proper divisors (1).
1401221262451 is an equidigital number, since it uses as much as digits as its factorization.
1401221262451 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 7680, while the sum is 31.
Adding to 1401221262451 its reverse (1542621221041), we get a palindrome (2943842483492).
The spelling of 1401221262451 in words is "one trillion, four hundred one billion, two hundred twenty-one million, two hundred sixty-two thousand, four hundred fifty-one".
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