1401224110001 has 4 divisors (see below), whose sum is σ = 1406551958592. Its totient is φ = 1395896261412.

The previous prime is 1401224109997. The next prime is 1401224110007. The reversal of 1401224110001 is 1000114221041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1401224110001 - 2² = 1401224109997 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1401224110007) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2663923901 + ... + 2663924426.

It is an arithmetic number, because the mean of its divisors is an integer number (351637989648).

Almost surely, 2^{1401224110001} is an apocalyptic number.

It is an amenable number.

1401224110001 is a deficient number, since it is larger than the sum of its proper divisors (5327848591).

1401224110001 is an equidigital number, since it uses as much as digits as its factorization.

1401224110001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5327848590.

The product of its (nonzero) digits is 64, while the sum is 17.

Adding to 1401224110001 its reverse (1000114221041), we get a palindrome (2401338331042).

The spelling of 1401224110001 in words is "one trillion, four hundred one billion, two hundred twenty-four million, one hundred ten thousand, one".