14012300012311 has 4 divisors (see below), whose sum is σ = 14019789217824. Its totient is φ = 14004810806800.

The previous prime is 14012300012303. The next prime is 14012300012323. The reversal of 14012300012311 is 11321000321041.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14012300012311 - 2³ = 14012300012303 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14012300012611) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3744599950 + ... + 3744603691.

It is an arithmetic number, because the mean of its divisors is an integer number (3504947304456).

Almost surely, 2^{14012300012311} is an apocalyptic number.

14012300012311 is a deficient number, since it is larger than the sum of its proper divisors (7489205513).

14012300012311 is an equidigital number, since it uses as much as digits as its factorization.

14012300012311 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7489205512.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 14012300012311 its reverse (11321000321041), we get a palindrome (25333300333352).

The spelling of 14012300012311 in words is "fourteen trillion, twelve billion, three hundred million, twelve thousand, three hundred eleven".