Base | Representation |
---|---|
bin | 1100101111100111111000… |
… | …1100000001111010100101 |
3 | 1211121120012022022010122121 |
4 | 3023321332030001322211 |
5 | 3314034142400333331 |
6 | 45445054551225541 |
7 | 2644232603140633 |
oct | 313717614017245 |
9 | 54546168263577 |
10 | 14012300402341 |
11 | 4512646305a5a |
12 | 16a38170782b1 |
13 | 7a847b3c7727 |
14 | 3662add26353 |
15 | 19475ac0bc11 |
hex | cbe7e301ea5 |
14012300402341 has 4 divisors (see below), whose sum is σ = 14013880686432. Its totient is φ = 14010720118252.
The previous prime is 14012300402293. The next prime is 14012300402357. The reversal of 14012300402341 is 14320400321041.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 14012300402341 - 27 = 14012300402213 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14012300402381) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 790128745 + ... + 790146478.
It is an arithmetic number, because the mean of its divisors is an integer number (3503470171608).
Almost surely, 214012300402341 is an apocalyptic number.
It is an amenable number.
14012300402341 is a deficient number, since it is larger than the sum of its proper divisors (1580284091).
14012300402341 is an equidigital number, since it uses as much as digits as its factorization.
14012300402341 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1580284090.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 14012300402341 its reverse (14320400321041), we get a palindrome (28332700723382).
The spelling of 14012300402341 in words is "fourteen trillion, twelve billion, three hundred million, four hundred two thousand, three hundred forty-one".
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