Base | Representation |
---|---|
bin | 1100101111100111111011… |
… | …0010001011000100111101 |
3 | 1211121120020000010010200221 |
4 | 3023321332302023010331 |
5 | 3314034202430320331 |
6 | 45445055545421341 |
7 | 2644233054134350 |
oct | 313717662130475 |
9 | 54546200103627 |
10 | 14012310401341 |
11 | 4512650a1539a |
12 | 16a381a49a851 |
13 | 7a84804b89b5 |
14 | 3662b13aa297 |
15 | 19475ba34711 |
hex | cbe7ec8b13d |
14012310401341 has 8 divisors (see below), whose sum is σ = 16045906149504. Its totient is φ = 11986673933040.
The previous prime is 14012310401333. The next prime is 14012310401503. The reversal of 14012310401341 is 14310401321041.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 14012310401341 - 23 = 14012310401333 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14012310401321) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1989816190 + ... + 1989823231.
It is an arithmetic number, because the mean of its divisors is an integer number (2005738268688).
Almost surely, 214012310401341 is an apocalyptic number.
It is an amenable number.
14012310401341 is a deficient number, since it is larger than the sum of its proper divisors (2033595748163).
14012310401341 is an equidigital number, since it uses as much as digits as its factorization.
14012310401341 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3979639931.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 14012310401341 its reverse (14310401321041), we get a palindrome (28322711722382).
The spelling of 14012310401341 in words is "fourteen trillion, twelve billion, three hundred ten million, four hundred one thousand, three hundred forty-one".
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