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140123234033342 = 2710008802430953
BaseRepresentation
bin11111110111000011111011…
…100101101101111010111110
3200101010122120002211001211022
4133313003323211231322332
5121331234340403031332
61214003420340024142
741341366236216110
oct3767037345557276
9611118502731738
10140123234033342
1140713a2567449a
12138709a3692052
136025744921361
142686001d5b3b0
15112edd8364212
hex7f70fb96debe

140123234033342 has 8 divisors (see below), whose sum is σ = 240211258342896. Its totient is φ = 60052814585712.

The previous prime is 140123234033339. The next prime is 140123234033369. The reversal of 140123234033342 is 243330432321041.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-3 number, since 3×1401232340333423 (a number of 43 digits) contains 333 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5004401215463 + ... + 5004401215490.

It is an arithmetic number, because the mean of its divisors is an integer number (30026407292862).

Almost surely, 2140123234033342 is an apocalyptic number.

140123234033342 is a deficient number, since it is larger than the sum of its proper divisors (100088024309554).

140123234033342 is a wasteful number, since it uses less digits than its factorization.

140123234033342 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10008802430962.

The product of its (nonzero) digits is 124416, while the sum is 35.

Adding to 140123234033342 its reverse (243330432321041), we get a palindrome (383453666354383).

The spelling of 140123234033342 in words is "one hundred forty trillion, one hundred twenty-three billion, two hundred thirty-four million, thirty-three thousand, three hundred forty-two".

Divisors: 1 2 7 14 10008802430953 20017604861906 70061617016671 140123234033342