Search a number
-
+
14012331323142 = 2310721826061251
BaseRepresentation
bin1100101111101000000000…
…0001111110111100000110
31211121120021110111002000110
43023322000001332330012
53314034223304320032
645445102014053450
72644233430023015
oct313720001767406
954546243432013
1014012331323142
114512661805239
1216a38254aa286
137a8484932869
143662b4094a7c
1519475d7b87cc
hexcbe8007ef06

14012331323142 has 16 divisors (see below), whose sum is σ = 28286575382592. Its totient is φ = 4627124985000.

The previous prime is 14012331323101. The next prime is 14012331323153. The reversal of 14012331323142 is 24132313321041.

It is a super-3 number, since 3×140123313231423 (a number of 40 digits) contains 333 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 10913029984 + ... + 10913031267.

It is an arithmetic number, because the mean of its divisors is an integer number (1767910961412).

Almost surely, 214012331323142 is an apocalyptic number.

14012331323142 is an abundant number, since it is smaller than the sum of its proper divisors (14274244059450).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

14012331323142 is a wasteful number, since it uses less digits than its factorization.

14012331323142 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 21826061363.

The product of its (nonzero) digits is 10368, while the sum is 30.

Adding to 14012331323142 its reverse (24132313321041), we get a palindrome (38144644644183).

The spelling of 14012331323142 in words is "fourteen trillion, twelve billion, three hundred thirty-one million, three hundred twenty-three thousand, one hundred forty-two".

Divisors: 1 2 3 6 107 214 321 642 21826061251 43652122502 65478183753 130956367506 2335388553857 4670777107714 7006165661571 14012331323142