Base | Representation |
---|---|
bin | 10100011001000001111… |
… | …100011101010010111011 |
3 | 11221221220121122022221012 |
4 | 110121001330131102323 |
5 | 140424243010044141 |
6 | 2551422123104135 |
7 | 203144445656342 |
oct | 24310174352273 |
9 | 4857817568835 |
10 | 1401265706171 |
11 | 4a0300a62051 |
12 | 1a76a907204b |
13 | a21a5bc5636 |
14 | 4bb70760b59 |
15 | 266b4328ceb |
hex | 14641f1d4bb |
1401265706171 has 2 divisors, whose sum is σ = 1401265706172. Its totient is φ = 1401265706170.
The previous prime is 1401265706131. The next prime is 1401265706201. The reversal of 1401265706171 is 1716075621041.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1401265706171 is a prime.
It is a super-2 number, since 2×14012657061712 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1401265706101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 700632853085 + 700632853086.
It is an arithmetic number, because the mean of its divisors is an integer number (700632853086).
Almost surely, 21401265706171 is an apocalyptic number.
1401265706171 is a deficient number, since it is larger than the sum of its proper divisors (1).
1401265706171 is an equidigital number, since it uses as much as digits as its factorization.
1401265706171 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 70560, while the sum is 41.
The spelling of 1401265706171 in words is "one trillion, four hundred one billion, two hundred sixty-five million, seven hundred six thousand, one hundred seventy-one".
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