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1401275151253 is a prime number
BaseRepresentation
bin10100011001000010100…
…000011111001110010101
311221221221021102012011001
4110121002200133032111
5140424302414320003
62551423101343301
7203144622155125
oct24310240371625
94857837365131
101401275151253
114a03063232aa
121a76b0267b31
13a21a7b51743
144bb71adcc85
15266b509261d
hex1464281f395

1401275151253 has 2 divisors, whose sum is σ = 1401275151254. Its totient is φ = 1401275151252.

The previous prime is 1401275151217. The next prime is 1401275151281. The reversal of 1401275151253 is 3521515721041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1197181728964 + 204093422289 = 1094158^2 + 451767^2 .

It is an emirp because it is prime and its reverse (3521515721041) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1401275151253 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1401275151293) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 700637575626 + 700637575627.

It is an arithmetic number, because the mean of its divisors is an integer number (700637575627).

Almost surely, 21401275151253 is an apocalyptic number.

It is an amenable number.

1401275151253 is a deficient number, since it is larger than the sum of its proper divisors (1).

1401275151253 is an equidigital number, since it uses as much as digits as its factorization.

1401275151253 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 42000, while the sum is 37.

The spelling of 1401275151253 in words is "one trillion, four hundred one billion, two hundred seventy-five million, one hundred fifty-one thousand, two hundred fifty-three".