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14013013134433 = 24488957221897
BaseRepresentation
bin1100101111101010100010…
…1010111000110001100001
31211121122000222102200021111
43023322220222320301201
53314042122330300213
645445253411423321
72644256346231025
oct313725052706141
954548028380244
1014013013134433
114512981661145
1216a39958b4b41
137a8562c740b1
1436633a856385
1519479d596a3d
hexcbea8ab8c61

14013013134433 has 4 divisors (see below), whose sum is σ = 14013070601220. Its totient is φ = 14012955667648.

The previous prime is 14013013134431. The next prime is 14013013134451. The reversal of 14013013134433 is 33443131031041.

It is a happy number.

14013013134433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 7164444515904 + 6848568618529 = 2676648^2 + 2616977^2 .

It is a cyclic number.

It is not a de Polignac number, because 14013013134433 - 21 = 14013013134431 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14013013134395 and 14013013134404.

It is not an unprimeable number, because it can be changed into a prime (14013013134431) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 28366060 + ... + 28855837.

It is an arithmetic number, because the mean of its divisors is an integer number (3503267650305).

Almost surely, 214013013134433 is an apocalyptic number.

It is an amenable number.

14013013134433 is a deficient number, since it is larger than the sum of its proper divisors (57466787).

14013013134433 is an equidigital number, since it uses as much as digits as its factorization.

14013013134433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 57466786.

The product of its (nonzero) digits is 15552, while the sum is 31.

Adding to 14013013134433 its reverse (33443131031041), we get a palindrome (47456144165474).

The spelling of 14013013134433 in words is "fourteen trillion, thirteen billion, thirteen million, one hundred thirty-four thousand, four hundred thirty-three".

Divisors: 1 244889 57221897 14013013134433