1401304040233 has 4 divisors (see below), whose sum is σ = 1421040716928. Its totient is φ = 1381567363540.

The previous prime is 1401304040231. The next prime is 1401304040251. The reversal of 1401304040233 is 3320404031041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1401304040233 - 2¹ = 1401304040231 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1401304040198 and 1401304040207.

It is not an unprimeable number, because it can be changed into a prime (1401304040231) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9868338241 + ... + 9868338382.

It is an arithmetic number, because the mean of its divisors is an integer number (355260179232).

Almost surely, 2^{1401304040233} is an apocalyptic number.

It is an amenable number.

1401304040233 is a deficient number, since it is larger than the sum of its proper divisors (19736676695).

1401304040233 is an equidigital number, since it uses as much as digits as its factorization.

1401304040233 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 19736676694.

The product of its (nonzero) digits is 3456, while the sum is 25.

Adding to 1401304040233 its reverse (3320404031041), we get a palindrome (4721708071274).

The spelling of 1401304040233 in words is "one trillion, four hundred one billion, three hundred four million, forty thousand, two hundred thirty-three".