Base | Representation |
---|---|
bin | 1100101111101010110111… |
… | …1111000100011111110100 |
3 | 1211121122021012020100002120 |
4 | 3023322231333010133310 |
5 | 3314042313142431122 |
6 | 45445310315035540 |
7 | 2644261511225151 |
oct | 313725577043764 |
9 | 54548235210076 |
10 | 14013102311412 |
11 | 4512a17a30126 |
12 | 16a39bb73bbb0 |
13 | 7a8578598539 |
14 | 36634862b228 |
15 | 1947a630e75c |
hex | cbeadfc47f4 |
14013102311412 has 96 divisors (see below), whose sum is σ = 33830573736960. Its totient is φ = 4512567671040.
The previous prime is 14013102311387. The next prime is 14013102311431. The reversal of 14013102311412 is 21411320131041.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 8819608 + ... + 10286480.
It is an arithmetic number, because the mean of its divisors is an integer number (352401809760).
Almost surely, 214013102311412 is an apocalyptic number.
14013102311412 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
14013102311412 is an abundant number, since it is smaller than the sum of its proper divisors (19817471425548).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
14013102311412 is a wasteful number, since it uses less digits than its factorization.
14013102311412 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1467173 (or 1467171 counting only the distinct ones).
The product of its (nonzero) digits is 576, while the sum is 24.
Adding to 14013102311412 its reverse (21411320131041), we get a palindrome (35424422442453).
The spelling of 14013102311412 in words is "fourteen trillion, thirteen billion, one hundred two million, three hundred eleven thousand, four hundred twelve".
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