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140131113 = 3421110951
BaseRepresentation
bin10000101101000…
…11101100101001
3100202200101202020
420112203230221
5241333143423
621523255053
73321044343
oct1026435451
9322611666
10140131113
1172111641
123ab1a489
1323054c25
141487a293
15c4804e3
hex85a3b29

140131113 has 8 divisors (see below), whose sum is σ = 187286976. Its totient is φ = 93198000.

The previous prime is 140131087. The next prime is 140131133. The reversal of 140131113 is 311131041.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 140131113 - 28 = 140130857 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 140131092 and 140131101.

It is not an unprimeable number, because it can be changed into a prime (140131133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 54213 + ... + 56738.

It is an arithmetic number, because the mean of its divisors is an integer number (23410872).

Almost surely, 2140131113 is an apocalyptic number.

It is an amenable number.

140131113 is a deficient number, since it is larger than the sum of its proper divisors (47155863).

140131113 is a wasteful number, since it uses less digits than its factorization.

140131113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 111375.

The product of its (nonzero) digits is 36, while the sum is 15.

The square root of 140131113 is about 11837.6988050888. The cubic root of 140131113 is about 519.4114556757.

Adding to 140131113 its reverse (311131041), we get a palindrome (451262154).

The spelling of 140131113 in words is "one hundred forty million, one hundred thirty-one thousand, one hundred thirteen".

Divisors: 1 3 421 1263 110951 332853 46710371 140131113