14013142131041 has 2 divisors, whose sum is σ = 14013142131042. Its totient is φ = 14013142131040.

The previous prime is 14013142131019. The next prime is 14013142131101. The reversal of 14013142131041 is 14013124131041.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10878486045025 + 3134656086016 = 3298255^2 + 1770496^2 .

It is a cyclic number.

It is not a de Polignac number, because 14013142131041 - 2¹⁰ = 14013142130017 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 14013142131041.

It is not a weakly prime, because it can be changed into another prime (14013142131941) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7006571065520 + 7006571065521.

It is an arithmetic number, because the mean of its divisors is an integer number (7006571065521).

Almost surely, 2^{14013142131041} is an apocalyptic number.

It is an amenable number.

14013142131041 is a deficient number, since it is larger than the sum of its proper divisors (1).

14013142131041 is an equidigital number, since it uses as much as digits as its factorization.

14013142131041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 26.

Adding to 14013142131041 its reverse (14013124131041), we get a palindrome (28026266262082).

The spelling of 14013142131041 in words is "fourteen trillion, thirteen billion, one hundred forty-two million, one hundred thirty-one thousand, forty-one".