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14013202431 = 34671067477
BaseRepresentation
bin11010000110100000…
…00111111111111111
31100011121022102220110
431003100013333333
5212144334434211
610234303321103
71004155153404
oct150320077777
940147272813
1014013202431
115a410a6438
122870bb0193
131424282277
1496d1522ab
1557038eea6
hex343407fff

14013202431 has 4 divisors (see below), whose sum is σ = 18684269912. Its totient is φ = 9342134952.

The previous prime is 14013202393. The next prime is 14013202439. The reversal of 14013202431 is 13420231041.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 14013202431 - 26 = 14013202367 is a prime.

It is a super-2 number, since 2×140132024312 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14013202398 and 14013202407.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14013202439) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2335533736 + ... + 2335533741.

It is an arithmetic number, because the mean of its divisors is an integer number (4671067478).

Almost surely, 214013202431 is an apocalyptic number.

14013202431 is a deficient number, since it is larger than the sum of its proper divisors (4671067481).

14013202431 is an equidigital number, since it uses as much as digits as its factorization.

14013202431 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4671067480.

The product of its (nonzero) digits is 576, while the sum is 21.

Adding to 14013202431 its reverse (13420231041), we get a palindrome (27433433472).

The spelling of 14013202431 in words is "fourteen billion, thirteen million, two hundred two thousand, four hundred thirty-one".

Divisors: 1 3 4671067477 14013202431