Base | Representation |
---|---|
bin | 11111110111001100010010… |
… | …001001101101010110100101 |
3 | 200101011111201010120110100011 |
4 | 133313030102021231112211 |
5 | 121331411222320022131 |
6 | 1214011502313250221 |
7 | 41342134420021525 |
oct | 3767142211552645 |
9 | 611144633513304 |
10 | 140132202501541 |
11 | 40717808089388 |
12 | 13872687103971 |
13 | 60265439b1383 |
14 | 26866130c5685 |
15 | 11302608b30b1 |
hex | 7f731226d5a5 |
140132202501541 has 2 divisors, whose sum is σ = 140132202501542. Its totient is φ = 140132202501540.
The previous prime is 140132202501427. The next prime is 140132202501601. The reversal of 140132202501541 is 145105202231041.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 116176277820100 + 23955924681441 = 10778510^2 + 4894479^2 .
It is a cyclic number.
It is not a de Polignac number, because 140132202501541 - 27 = 140132202501413 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (140132262501541) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70066101250770 + 70066101250771.
It is an arithmetic number, because the mean of its divisors is an integer number (70066101250771).
Almost surely, 2140132202501541 is an apocalyptic number.
It is an amenable number.
140132202501541 is a deficient number, since it is larger than the sum of its proper divisors (1).
140132202501541 is an equidigital number, since it uses as much as digits as its factorization.
140132202501541 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9600, while the sum is 31.
Adding to 140132202501541 its reverse (145105202231041), we get a palindrome (285237404732582).
The spelling of 140132202501541 in words is "one hundred forty trillion, one hundred thirty-two billion, two hundred two million, five hundred one thousand, five hundred forty-one".
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