Base | Representation |
---|---|
bin | 11010000110100000… |
… | …10100100110001111 |
3 | 1100011121102001200120 |
4 | 31003100110212033 |
5 | 212144343112111 |
6 | 10234304400023 |
7 | 1004155460010 |
oct | 150320244617 |
9 | 40147361616 |
10 | 14013254031 |
11 | 5a41131187 |
12 | 2871016013 |
13 | 142429c8ba |
14 | 96d167007 |
15 | 5703a0406 |
hex | 34341498f |
14013254031 has 16 divisors (see below), whose sum is σ = 21379008000. Its totient is φ = 7998019488.
The previous prime is 14013254029. The next prime is 14013254083. The reversal of 14013254031 is 13045231041.
It is a happy number.
It is not a de Polignac number, because 14013254031 - 21 = 14013254029 is a prime.
It is a super-2 number, since 2×140132540312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 14013253992 and 14013254010.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14013254011) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 380056 + ... + 415293.
It is an arithmetic number, because the mean of its divisors is an integer number (1336188000).
Almost surely, 214013254031 is an apocalyptic number.
14013254031 is a deficient number, since it is larger than the sum of its proper divisors (7365753969).
14013254031 is an equidigital number, since it uses as much as digits as its factorization.
14013254031 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 796198.
The product of its (nonzero) digits is 1440, while the sum is 24.
Adding to 14013254031 its reverse (13045231041), we get a palindrome (27058485072).
The spelling of 14013254031 in words is "fourteen billion, thirteen million, two hundred fifty-four thousand, thirty-one".
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