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14013254031 = 37839795349
BaseRepresentation
bin11010000110100000…
…10100100110001111
31100011121102001200120
431003100110212033
5212144343112111
610234304400023
71004155460010
oct150320244617
940147361616
1014013254031
115a41131187
122871016013
13142429c8ba
1496d167007
155703a0406
hex34341498f

14013254031 has 16 divisors (see below), whose sum is σ = 21379008000. Its totient is φ = 7998019488.

The previous prime is 14013254029. The next prime is 14013254083. The reversal of 14013254031 is 13045231041.

It is a happy number.

It is not a de Polignac number, because 14013254031 - 21 = 14013254029 is a prime.

It is a super-2 number, since 2×140132540312 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 14013253992 and 14013254010.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14013254011) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 380056 + ... + 415293.

It is an arithmetic number, because the mean of its divisors is an integer number (1336188000).

Almost surely, 214013254031 is an apocalyptic number.

14013254031 is a deficient number, since it is larger than the sum of its proper divisors (7365753969).

14013254031 is an equidigital number, since it uses as much as digits as its factorization.

14013254031 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 796198.

The product of its (nonzero) digits is 1440, while the sum is 24.

Adding to 14013254031 its reverse (13045231041), we get a palindrome (27058485072).

The spelling of 14013254031 in words is "fourteen billion, thirteen million, two hundred fifty-four thousand, thirty-one".

Divisors: 1 3 7 21 839 2517 5873 17619 795349 2386047 5567443 16702329 667297811 2001893433 4671084677 14013254031