Search a number
-
+
14013313444001 is a prime number
BaseRepresentation
bin1100101111101011101010…
…0100011110100010100001
31211121122210220111222120002
43023322322210132202201
53314043231220202001
645445343300225345
72644266653640104
oct313727244364241
954548726458502
1014013313444001
114513016127173
1216a3a5a39b255
137a85b024ca71
143663686aa73b
151947b9b1746b
hexcbeba91e8a1

14013313444001 has 2 divisors, whose sum is σ = 14013313444002. Its totient is φ = 14013313444000.

The previous prime is 14013313443947. The next prime is 14013313444051. The reversal of 14013313444001 is 10044431331041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10301217621601 + 3712095822400 = 3209551^2 + 1926680^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14013313444001 is a prime.

It is not a weakly prime, because it can be changed into another prime (14013313444051) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7006656722000 + 7006656722001.

It is an arithmetic number, because the mean of its divisors is an integer number (7006656722001).

Almost surely, 214013313444001 is an apocalyptic number.

It is an amenable number.

14013313444001 is a deficient number, since it is larger than the sum of its proper divisors (1).

14013313444001 is an equidigital number, since it uses as much as digits as its factorization.

14013313444001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 14013313444001 its reverse (10044431331041), we get a palindrome (24057744775042).

The spelling of 14013313444001 in words is "fourteen trillion, thirteen billion, three hundred thirteen million, four hundred forty-four thousand, one".