14013412051 has 2 divisors, whose sum is σ = 14013412052. Its totient is φ = 14013412050.

The previous prime is 14013412033. The next prime is 14013412093. The reversal of 14013412051 is 15021431041.

14013412051 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is an emirp because it is prime and its reverse (15021431041) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14013412051 - 2⁹ = 14013411539 is a prime.

It is a super-2 number, since 2×14013412051² (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (14013412151) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7006706025 + 7006706026.

It is an arithmetic number, because the mean of its divisors is an integer number (7006706026).

Almost surely, 2^14013412051 is an apocalyptic number.

14013412051 is a deficient number, since it is larger than the sum of its proper divisors (1).

14013412051 is an equidigital number, since it uses as much as digits as its factorization.

14013412051 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 480, while the sum is 22.

Adding to 14013412051 its reverse (15021431041), we get a palindrome (29034843092).

The spelling of 14013412051 in words is "fourteen billion, thirteen million, four hundred twelve thousand, fifty-one".