1401341421233 has 4 divisors (see below), whose sum is σ = 1509136915188. Its totient is φ = 1293545927280.

The previous prime is 1401341421229. The next prime is 1401341421239. The reversal of 1401341421233 is 3321241431041.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 136757956864 + 1264583464369 = 369808^2 + 1124537^2 .

It is a cyclic number.

It is not a de Polignac number, because 1401341421233 - 2² = 1401341421229 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1401341421196 and 1401341421205.

It is not an unprimeable number, because it can be changed into a prime (1401341421239) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 53897746958 + ... + 53897746983.

It is an arithmetic number, because the mean of its divisors is an integer number (377284228797).

Almost surely, 2^{1401341421233} is an apocalyptic number.

1401341421233 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

1401341421233 is a deficient number, since it is larger than the sum of its proper divisors (107795493955).

1401341421233 is a wasteful number, since it uses less digits than its factorization.

1401341421233 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 107795493954.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 1401341421233 its reverse (3321241431041), we get a palindrome (4722582852274).

The spelling of 1401341421233 in words is "one trillion, four hundred one billion, three hundred forty-one million, four hundred twenty-one thousand, two hundred thirty-three".