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140134510104103 = 174180490815683
BaseRepresentation
bin11111110111001110011011…
…101100100000111000100111
3200101011201122221201210221201
4133313032123230200320213
5121331430434041312403
61214012523305223331
741342245540226014
oct3767163354407047
9611151587653851
10140134510104103
1140718791722339
121387300ba91b47
136026820ab8a88
14268679177270b
15113034828721d
hex7f739bb20e27

140134510104103 has 4 divisors (see below), whose sum is σ = 140215000921528. Its totient is φ = 140054019286680.

The previous prime is 140134510104047. The next prime is 140134510104161. The reversal of 140134510104103 is 301401015431041.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-140134510104103 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (140134510104163) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 40245406101 + ... + 40245409582.

It is an arithmetic number, because the mean of its divisors is an integer number (35053750230382).

Almost surely, 2140134510104103 is an apocalyptic number.

140134510104103 is a deficient number, since it is larger than the sum of its proper divisors (80490817425).

140134510104103 is an equidigital number, since it uses as much as digits as its factorization.

140134510104103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 80490817424.

The product of its (nonzero) digits is 2880, while the sum is 28.

Adding to 140134510104103 its reverse (301401015431041), we get a palindrome (441535525535144).

The spelling of 140134510104103 in words is "one hundred forty trillion, one hundred thirty-four billion, five hundred ten million, one hundred four thousand, one hundred three".

Divisors: 1 1741 80490815683 140134510104103