14013780655957 has 4 divisors (see below), whose sum is σ = 14103040405516. Its totient is φ = 13924520906400.

The previous prime is 14013780655951. The next prime is 14013780655991. The reversal of 14013780655957 is 75955608731041.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 9588925366801 + 4424855289156 = 3096599^2 + 2103534^2 .

It is a cyclic number.

It is not a de Polignac number, because 14013780655957 - 2³ = 14013780655949 is a prime.

It is a super-3 number, since 3×14013780655957³ (a number of 40 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14013780655895 and 14013780655904.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14013780655951) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 44629874544 + ... + 44629874857.

It is an arithmetic number, because the mean of its divisors is an integer number (3525760101379).

Almost surely, 2^{14013780655957} is an apocalyptic number.

It is an amenable number.

14013780655957 is a deficient number, since it is larger than the sum of its proper divisors (89259749559).

14013780655957 is an equidigital number, since it uses as much as digits as its factorization.

14013780655957 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 89259749558.

The product of its (nonzero) digits is 31752000, while the sum is 61.

The spelling of 14013780655957 in words is "fourteen trillion, thirteen billion, seven hundred eighty million, six hundred fifty-five thousand, nine hundred fifty-seven".