1401411113 has 2 divisors, whose sum is σ = 1401411114. Its totient is φ = 1401411112.

The previous prime is 1401411103. The next prime is 1401411127. The reversal of 1401411113 is 3111141041.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1000330384 + 401080729 = 31628^2 + 20027^2 .

It is a cyclic number.

It is not a de Polignac number, because 1401411113 - 2⁶ = 1401411049 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 1401411091 and 1401411100.

It is not a weakly prime, because it can be changed into another prime (1401411103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 700705556 + 700705557.

It is an arithmetic number, because the mean of its divisors is an integer number (700705557).

Almost surely, 2^1401411113 is an apocalyptic number.

It is an amenable number.

1401411113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1401411113 is an equidigital number, since it uses as much as digits as its factorization.

1401411113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48, while the sum is 17.

The square root of 1401411113 is about 37435.4259091572. The cubic root of 1401411113 is about 1119.0646721838.

Adding to 1401411113 its reverse (3111141041), we get a palindrome (4512552154).

The spelling of 1401411113 in words is "one billion, four hundred one million, four hundred eleven thousand, one hundred thirteen".