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1401411439997 is a prime number
BaseRepresentation
bin10100011001001010101…
…000011000110101111101
311221222021202212101011022
4110121022220120311331
5140430042312034442
62551444410433525
7203151165460322
oct24311250306575
94858252771138
101401411439997
114a0376250028
121a7729a328a5
13a21ca15c77a
144bb85c58b49
15266c20143d2
hex1464aa18d7d

1401411439997 has 2 divisors, whose sum is σ = 1401411439998. Its totient is φ = 1401411439996.

The previous prime is 1401411439957. The next prime is 1401411440029. The reversal of 1401411439997 is 7999341141041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1376424050521 + 24987389476 = 1173211^2 + 158074^2 .

It is a cyclic number.

It is not a de Polignac number, because 1401411439997 - 230 = 1400337698173 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1401411439937) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 700705719998 + 700705719999.

It is an arithmetic number, because the mean of its divisors is an integer number (700705719999).

Almost surely, 21401411439997 is an apocalyptic number.

It is an amenable number.

1401411439997 is a deficient number, since it is larger than the sum of its proper divisors (1).

1401411439997 is an equidigital number, since it uses as much as digits as its factorization.

1401411439997 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 979776, while the sum is 53.

The spelling of 1401411439997 in words is "one trillion, four hundred one billion, four hundred eleven million, four hundred thirty-nine thousand, nine hundred ninety-seven".