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140141172039689 is a prime number
BaseRepresentation
bin11111110111010100101000…
…110001110010000000001001
3200101012100212020100012112202
4133313110220301302000021
5121332033110020232224
61214015544325445545
741342602612601522
oct3767245061620011
9611170766305482
10140141172039689
11407205a0164127
121387436ab708b5
1360273430573b2
142686c2444b849
1511305d8073eae
hex7f7528c72009

140141172039689 has 2 divisors, whose sum is σ = 140141172039690. Its totient is φ = 140141172039688.

The previous prime is 140141172039667. The next prime is 140141172039691. The reversal of 140141172039689 is 986930271141041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 139843230734089 + 297941305600 = 11825533^2 + 545840^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-140141172039689 is a prime.

Together with 140141172039691, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (140141172039389) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70070586019844 + 70070586019845.

It is an arithmetic number, because the mean of its divisors is an integer number (70070586019845).

Almost surely, 2140141172039689 is an apocalyptic number.

It is an amenable number.

140141172039689 is a deficient number, since it is larger than the sum of its proper divisors (1).

140141172039689 is an equidigital number, since it uses as much as digits as its factorization.

140141172039689 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2612736, while the sum is 56.

The spelling of 140141172039689 in words is "one hundred forty trillion, one hundred forty-one billion, one hundred seventy-two million, thirty-nine thousand, six hundred eighty-nine".