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1401413200241 is a prime number
BaseRepresentation
bin10100011001001010101…
…111000110100101110001
311221222021220011210202112
4110121022233012211301
5140430043234401431
62551444512255105
7203151216441245
oct24311257064561
94858256153675
101401413200241
114a037724257a
121a772a541495
13a21ca627a32
144bb86196425
15266c2260c2b
hex1464abc6971

1401413200241 has 2 divisors, whose sum is σ = 1401413200242. Its totient is φ = 1401413200240.

The previous prime is 1401413200223. The next prime is 1401413200247. The reversal of 1401413200241 is 1420023141041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 996560961841 + 404852238400 = 998279^2 + 636280^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1401413200241 is a prime.

It is not a weakly prime, because it can be changed into another prime (1401413200247) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 700706600120 + 700706600121.

It is an arithmetic number, because the mean of its divisors is an integer number (700706600121).

Almost surely, 21401413200241 is an apocalyptic number.

It is an amenable number.

1401413200241 is a deficient number, since it is larger than the sum of its proper divisors (1).

1401413200241 is an equidigital number, since it uses as much as digits as its factorization.

1401413200241 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 768, while the sum is 23.

Adding to 1401413200241 its reverse (1420023141041), we get a palindrome (2821436341282).

The spelling of 1401413200241 in words is "one trillion, four hundred one billion, four hundred thirteen million, two hundred thousand, two hundred forty-one".