14015113 has 4 divisors (see below), whose sum is σ = 16017280. Its totient is φ = 12012948.

The previous prime is 14015083. The next prime is 14015117. The reversal of 14015113 is 31151041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14015113 - 2¹³ = 14006921 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14015117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1001073 + ... + 1001086.

It is an arithmetic number, because the mean of its divisors is an integer number (4004320).

Almost surely, 2^14015113 is an apocalyptic number.

It is an amenable number.

14015113 is a deficient number, since it is larger than the sum of its proper divisors (2002167).

14015113 is an equidigital number, since it uses as much as digits as its factorization.

14015113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2002166.

The product of its (nonzero) digits is 60, while the sum is 16.

The square root of 14015113 is about 3743.6764016138. The cubic root of 14015113 is about 241.1009201822.

Adding to 14015113 its reverse (31151041), we get a palindrome (45166154).

The spelling of 14015113 in words is "fourteen million, fifteen thousand, one hundred thirteen".