Base | Representation |
---|---|
bin | 10100011001010000101… |
… | …101011111010101100011 |
3 | 11221222112212210112200211 |
4 | 110121100231133111203 |
5 | 140430244420044421 |
6 | 2551502452554551 |
7 | 203153544454234 |
oct | 24312055372543 |
9 | 4858485715624 |
10 | 1401513440611 |
11 | 4a0418888659 |
12 | 1a7758022a57 |
13 | a2215323a6b |
14 | 4bb9560b08b |
15 | 266cae619e1 |
hex | 14650b5f563 |
1401513440611 has 2 divisors, whose sum is σ = 1401513440612. Its totient is φ = 1401513440610.
The previous prime is 1401513440531. The next prime is 1401513440617. The reversal of 1401513440611 is 1160443151041.
It is a strong prime.
It is an emirp because it is prime and its reverse (1160443151041) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1401513440611 - 215 = 1401513407843 is a prime.
It is not a weakly prime, because it can be changed into another prime (1401513440617) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 700756720305 + 700756720306.
It is an arithmetic number, because the mean of its divisors is an integer number (700756720306).
Almost surely, 21401513440611 is an apocalyptic number.
1401513440611 is a deficient number, since it is larger than the sum of its proper divisors (1).
1401513440611 is an equidigital number, since it uses as much as digits as its factorization.
1401513440611 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5760, while the sum is 31.
Adding to 1401513440611 its reverse (1160443151041), we get a palindrome (2561956591652).
The spelling of 1401513440611 in words is "one trillion, four hundred one billion, five hundred thirteen million, four hundred forty thousand, six hundred eleven".
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