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1401513440611 is a prime number
BaseRepresentation
bin10100011001010000101…
…101011111010101100011
311221222112212210112200211
4110121100231133111203
5140430244420044421
62551502452554551
7203153544454234
oct24312055372543
94858485715624
101401513440611
114a0418888659
121a7758022a57
13a2215323a6b
144bb9560b08b
15266cae619e1
hex14650b5f563

1401513440611 has 2 divisors, whose sum is σ = 1401513440612. Its totient is φ = 1401513440610.

The previous prime is 1401513440531. The next prime is 1401513440617. The reversal of 1401513440611 is 1160443151041.

It is a strong prime.

It is an emirp because it is prime and its reverse (1160443151041) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1401513440611 - 215 = 1401513407843 is a prime.

It is not a weakly prime, because it can be changed into another prime (1401513440617) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 700756720305 + 700756720306.

It is an arithmetic number, because the mean of its divisors is an integer number (700756720306).

Almost surely, 21401513440611 is an apocalyptic number.

1401513440611 is a deficient number, since it is larger than the sum of its proper divisors (1).

1401513440611 is an equidigital number, since it uses as much as digits as its factorization.

1401513440611 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5760, while the sum is 31.

Adding to 1401513440611 its reverse (1160443151041), we get a palindrome (2561956591652).

The spelling of 1401513440611 in words is "one trillion, four hundred one billion, five hundred thirteen million, four hundred forty thousand, six hundred eleven".