1160443151041 has 2 divisors, whose sum is σ = 1160443151042. Its totient is φ = 1160443151040.

The previous prime is 1160443151039. The next prime is 1160443151051. The reversal of 1160443151041 is 1401513440611.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 951590495025 + 208852656016 = 975495^2 + 457004^2 .

It is an emirp because it is prime and its reverse (1401513440611) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1160443151041 - 2¹ = 1160443151039 is a prime.

Together with 1160443151039, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 1160443150994 and 1160443151012.

It is not a weakly prime, because it can be changed into another prime (1160443151051) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 580221575520 + 580221575521.

It is an arithmetic number, because the mean of its divisors is an integer number (580221575521).

Almost surely, 2^{1160443151041} is an apocalyptic number.

It is an amenable number.

1160443151041 is a deficient number, since it is larger than the sum of its proper divisors (1).

1160443151041 is an equidigital number, since it uses as much as digits as its factorization.

1160443151041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5760, while the sum is 31.

Adding to 1160443151041 its reverse (1401513440611), we get a palindrome (2561956591652).

The spelling of 1160443151041 in words is "one trillion, one hundred sixty billion, four hundred forty-three million, one hundred fifty-one thousand, forty-one".