Base | Representation |
---|---|
bin | 10100011001011011111… |
… | …001110100101111101011 |
3 | 11222000000222010220021001 |
4 | 110121123321310233223 |
5 | 140431141003122103 |
6 | 2551533241455431 |
7 | 203161314546025 |
oct | 24313371645753 |
9 | 4860028126231 |
10 | 1401701223403 |
11 | 4a0504886648 |
12 | 1a77aaaa1577 |
13 | a22451c1240 |
14 | 4bbb252d015 |
15 | 266dc6a601d |
hex | 1465be74beb |
1401701223403 has 4 divisors (see below), whose sum is σ = 1509524394448. Its totient is φ = 1293878052360.
The previous prime is 1401701223341. The next prime is 1401701223421. The reversal of 1401701223403 is 3043221071041.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1401701223403 - 221 = 1401699126251 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1401701223443) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 53911585503 + ... + 53911585528.
It is an arithmetic number, because the mean of its divisors is an integer number (377381098612).
Almost surely, 21401701223403 is an apocalyptic number.
1401701223403 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
1401701223403 is a deficient number, since it is larger than the sum of its proper divisors (107823171045).
1401701223403 is a wasteful number, since it uses less digits than its factorization.
1401701223403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 107823171044.
The product of its (nonzero) digits is 4032, while the sum is 28.
Adding to 1401701223403 its reverse (3043221071041), we get a palindrome (4444922294444).
The spelling of 1401701223403 in words is "one trillion, four hundred one billion, seven hundred one million, two hundred twenty-three thousand, four hundred three".
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