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14020001123 is a prime number
BaseRepresentation
bin11010000111010100…
…00011110101100011
31100012002002211221212
431003222003311203
5212203110013443
610235105140335
71004300020562
oct150352036543
940162084855
1014020001123
115a44a1a397
12287332a6ab
1314257c296b
14970001bd9
15570c84618
hex343a83d63

14020001123 has 2 divisors, whose sum is σ = 14020001124. Its totient is φ = 14020001122.

The previous prime is 14020001087. The next prime is 14020001147. The reversal of 14020001123 is 32110002041.

14020001123 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 14020001123 - 26 = 14020001059 is a prime.

It is a super-2 number, since 2×140200011232 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 14020001098 and 14020001107.

It is not a weakly prime, because it can be changed into another prime (14020001173) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7010000561 + 7010000562.

It is an arithmetic number, because the mean of its divisors is an integer number (7010000562).

Almost surely, 214020001123 is an apocalyptic number.

14020001123 is a deficient number, since it is larger than the sum of its proper divisors (1).

14020001123 is an equidigital number, since it uses as much as digits as its factorization.

14020001123 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 14.

Adding to 14020001123 its reverse (32110002041), we get a palindrome (46130003164).

The spelling of 14020001123 in words is "fourteen billion, twenty million, one thousand, one hundred twenty-three".