140201031319 has 2 divisors, whose sum is σ = 140201031320. Its totient is φ = 140201031318.

The previous prime is 140201031287. The next prime is 140201031337. The reversal of 140201031319 is 913130102041.

It is a strong prime.

It is an emirp because it is prime and its reverse (913130102041) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 140201031319 - 2⁵ = 140201031287 is a prime.

It is a super-2 number, since 2×140201031319² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 140201031293 and 140201031302.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (140201031359) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70100515659 + 70100515660.

It is an arithmetic number, because the mean of its divisors is an integer number (70100515660).

Almost surely, 2^140201031319 is an apocalyptic number.

140201031319 is a deficient number, since it is larger than the sum of its proper divisors (1).

140201031319 is an equidigital number, since it uses as much as digits as its factorization.

140201031319 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 648, while the sum is 25.

The spelling of 140201031319 in words is "one hundred forty billion, two hundred one million, thirty-one thousand, three hundred nineteen".