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140201324345 = 543652099183
BaseRepresentation
bin1000001010010010100…
…1100110111100111001
3111101212212112012211102
42002210221212330321
54244113014334340
6144224012541145
713062214410515
oct2024451467471
9441785465742
10140201324345
1154505aa10a5
12232091817b5
13102b44c1024
146b00277145
1539a873d215
hex20a4a66f39

140201324345 has 8 divisors (see below), whose sum is σ = 172154184576. Its totient is φ = 109552662576.

The previous prime is 140201324339. The next prime is 140201324369. The reversal of 140201324345 is 543423102041.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 140201324345 - 26 = 140201324281 is a prime.

It is a super-2 number, since 2×1402013243452 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 326049377 + ... + 326049806.

It is an arithmetic number, because the mean of its divisors is an integer number (21519273072).

Almost surely, 2140201324345 is an apocalyptic number.

It is an amenable number.

140201324345 is a deficient number, since it is larger than the sum of its proper divisors (31952860231).

140201324345 is an equidigital number, since it uses as much as digits as its factorization.

140201324345 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 652099231.

The product of its (nonzero) digits is 11520, while the sum is 29.

Adding to 140201324345 its reverse (543423102041), we get a palindrome (683624426386).

The spelling of 140201324345 in words is "one hundred forty billion, two hundred one million, three hundred twenty-four thousand, three hundred forty-five".

Divisors: 1 5 43 215 652099183 3260495915 28040264869 140201324345