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14020400003 = 611791284037
BaseRepresentation
bin11010000111010111…
…00101001110000011
31100012002212010010012
431003223211032003
5212203210300003
610235121455135
71004303301521
oct150353451603
940162763105
1014020400003
115a45172045
1228734a14ab
13142590239c
149700a7311
15570d128d8
hex343ae5383

14020400003 has 8 divisors (see below), whose sum is σ = 14329864080. Its totient is φ = 13713504480.

The previous prime is 14020399999. The next prime is 14020400071. The reversal of 14020400003 is 30000402041.

14020400003 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 14020400003 - 22 = 14020399999 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14020406003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 631100 + ... + 652937.

It is an arithmetic number, because the mean of its divisors is an integer number (1791233010).

Almost surely, 214020400003 is an apocalyptic number.

14020400003 is a deficient number, since it is larger than the sum of its proper divisors (309464077).

14020400003 is a wasteful number, since it uses less digits than its factorization.

14020400003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1284277.

The product of its (nonzero) digits is 96, while the sum is 14.

Adding to 14020400003 its reverse (30000402041), we get a palindrome (44020802044).

The spelling of 14020400003 in words is "fourteen billion, twenty million, four hundred thousand, three".

Divisors: 1 61 179 10919 1284037 78326257 229842623 14020400003