Base | Representation |
---|---|
bin | 11111111000010101101011… |
… | …001010001111001001001111 |
3 | 200101110001010000210111122002 |
4 | 133320111223022033021033 |
5 | 121334204114314123003 |
6 | 1214112014021142515 |
7 | 41350624263062564 |
oct | 3770255312171117 |
9 | 611401100714562 |
10 | 140211005223503 |
11 | 40748176178785 |
12 | 138859b9b5aa3b |
13 | 6030ac1a65936 |
14 | 268a36ac3c86b |
15 | 1132323bd2a88 |
hex | 7f856b28f24f |
140211005223503 has 2 divisors, whose sum is σ = 140211005223504. Its totient is φ = 140211005223502.
The previous prime is 140211005223451. The next prime is 140211005223521. The reversal of 140211005223503 is 305322500112041.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 140211005223503 - 228 = 140210736788047 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (140211005223403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70105502611751 + 70105502611752.
It is an arithmetic number, because the mean of its divisors is an integer number (70105502611752).
Almost surely, 2140211005223503 is an apocalyptic number.
140211005223503 is a deficient number, since it is larger than the sum of its proper divisors (1).
140211005223503 is an equidigital number, since it uses as much as digits as its factorization.
140211005223503 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 7200, while the sum is 29.
Adding to 140211005223503 its reverse (305322500112041), we get a palindrome (445533505335544).
The spelling of 140211005223503 in words is "one hundred forty trillion, two hundred eleven billion, five million, two hundred twenty-three thousand, five hundred three".
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