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14021144013403 = 17824773177259
BaseRepresentation
bin1100110000001000110101…
…0011101110101001011011
31211122102000122010010101001
43030002031103232221123
53314210300331412103
645453120304405431
72644665006452362
oct314021523565133
954572018103331
1014021144013403
1145163742a092a
1216a5484916877
137a925a64ca97
143668ac66c7d9
15194ac72e601d
hexcc08d4eea5b

14021144013403 has 4 divisors (see below), whose sum is σ = 14845917190680. Its totient is φ = 13196370836128.

The previous prime is 14021144013389. The next prime is 14021144013421. The reversal of 14021144013403 is 30431044112041.

14021144013403 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14021144013403 - 29 = 14021144012891 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14021144013433) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 412386588613 + ... + 412386588646.

It is an arithmetic number, because the mean of its divisors is an integer number (3711479297670).

Almost surely, 214021144013403 is an apocalyptic number.

14021144013403 is a deficient number, since it is larger than the sum of its proper divisors (824773177277).

14021144013403 is an equidigital number, since it uses as much as digits as its factorization.

14021144013403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 824773177276.

The product of its (nonzero) digits is 4608, while the sum is 28.

Adding to 14021144013403 its reverse (30431044112041), we get a palindrome (44452188125444).

The spelling of 14021144013403 in words is "fourteen trillion, twenty-one billion, one hundred forty-four million, thirteen thousand, four hundred three".

Divisors: 1 17 824773177259 14021144013403