14021310013003 has 4 divisors (see below), whose sum is σ = 14021339142568. Its totient is φ = 14021280883440.

The previous prime is 14021310012977. The next prime is 14021310013019. The reversal of 14021310013003 is 30031001312041.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14021310013003 - 2⁹ = 14021310012491 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14021310013033) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13830426 + ... + 14809567.

It is an arithmetic number, because the mean of its divisors is an integer number (3505334785642).

Almost surely, 2^{14021310013003} is an apocalyptic number.

14021310013003 is a deficient number, since it is larger than the sum of its proper divisors (29129565).

14021310013003 is an equidigital number, since it uses as much as digits as its factorization.

14021310013003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 29129564.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 14021310013003 its reverse (30031001312041), we get a palindrome (44052311325044).

The spelling of 14021310013003 in words is "fourteen trillion, twenty-one billion, three hundred ten million, thirteen thousand, three".