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140213109945149 is a prime number
BaseRepresentation
bin11111111000010111101000…
…100111000111001100111101
3200101110020112201012102221122
4133320113220213013030331
5121334222422121221044
61214113002524440325
741351030400653363
oct3770275047071475
9611406481172848
10140213109945149
114074905624125a
12138862a69a90a5
136031068b17967
14268a4ca597633
1511323e887ddee
hex7f85e89c733d

140213109945149 has 2 divisors, whose sum is σ = 140213109945150. Its totient is φ = 140213109945148.

The previous prime is 140213109945143. The next prime is 140213109945157. The reversal of 140213109945149 is 941549901312041.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 133314318777124 + 6898791168025 = 11546182^2 + 2626555^2 .

It is a cyclic number.

It is not a de Polignac number, because 140213109945149 - 240 = 139113598317373 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 140213109945149.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (140213109945143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70106554972574 + 70106554972575.

It is an arithmetic number, because the mean of its divisors is an integer number (70106554972575).

Almost surely, 2140213109945149 is an apocalyptic number.

It is an amenable number.

140213109945149 is a deficient number, since it is larger than the sum of its proper divisors (1).

140213109945149 is an equidigital number, since it uses as much as digits as its factorization.

140213109945149 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1399680, while the sum is 53.

The spelling of 140213109945149 in words is "one hundred forty trillion, two hundred thirteen billion, one hundred nine million, nine hundred forty-five thousand, one hundred forty-nine".