Base | Representation |
---|---|
bin | 11111111000010111101000… |
… | …101011111001100011101111 |
3 | 200101110020112210120012020222 |
4 | 133320113220223321203233 |
5 | 121334222422431344413 |
6 | 1214113003011401555 |
7 | 41351030414430653 |
oct | 3770275053714357 |
9 | 611406483505228 |
10 | 140213111199983 |
11 | 40749056a19008 |
12 | 138862a72b32bb |
13 | 6031069166b73 |
14 | 268a4ca802a63 |
15 | 11323e8a2ab08 |
hex | 7f85e8af98ef |
140213111199983 has 2 divisors, whose sum is σ = 140213111199984. Its totient is φ = 140213111199982.
The previous prime is 140213111199961. The next prime is 140213111200003. The reversal of 140213111199983 is 389991111312041.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 140213111199983 - 230 = 140212037458159 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (140213111199923) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70106555599991 + 70106555599992.
It is an arithmetic number, because the mean of its divisors is an integer number (70106555599992).
Almost surely, 2140213111199983 is an apocalyptic number.
140213111199983 is a deficient number, since it is larger than the sum of its proper divisors (1).
140213111199983 is an equidigital number, since it uses as much as digits as its factorization.
140213111199983 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 419904, while the sum is 53.
The spelling of 140213111199983 in words is "one hundred forty trillion, two hundred thirteen billion, one hundred eleven million, one hundred ninety-nine thousand, nine hundred eighty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •