140213111320134 has 64 divisors (see below), whose sum is σ = 312057083796480. Its totient is φ = 46666852103520.

The previous prime is 140213111320133. The next prime is 140213111320147. The reversal of 140213111320134 is 431023111312041.

140213111320134 is a `hidden beast` number, since 1 + 4 + 0 + 21 + 311 + 1 + 320 + 1 + 3 + 4 = 666.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 140213111320098 and 140213111320107.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (140213111320133) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 798296844 + ... + 798472464.

It is an arithmetic number, because the mean of its divisors is an integer number (4875891934320).

Almost surely, 2^{140213111320134} is an apocalyptic number.

140213111320134 is an abundant number, since it is smaller than the sum of its proper divisors (171843972476346).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

140213111320134 is a wasteful number, since it uses less digits than its factorization.

140213111320134 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 197962 (or 197956 counting only the distinct ones).

The product of its (nonzero) digits is 1728, while the sum is 27.

Adding to 140213111320134 its reverse (431023111312041), we get a palindrome (571236222632175).

The spelling of 140213111320134 in words is "one hundred forty trillion, two hundred thirteen billion, one hundred eleven million, three hundred twenty thousand, one hundred thirty-four".