Base | Representation |
---|---|
bin | 1100110000001001011111… |
… | …1010101111001010111001 |
3 | 1211122102111001001100121112 |
4 | 3030002113322233022321 |
5 | 3314211131413330241 |
6 | 45453150103450105 |
7 | 2645002300431632 |
oct | 314022772571271 |
9 | 54572431040545 |
10 | 14021322011321 |
11 | 4516455816349 |
12 | 16a5514456935 |
13 | 7a92884a25b1 |
14 | 3668c8164889 |
15 | 194ad7c561eb |
hex | cc097eaf2b9 |
14021322011321 has 4 divisors (see below), whose sum is σ = 14021501410944. Its totient is φ = 14021142611700.
The previous prime is 14021322011299. The next prime is 14021322011377. The reversal of 14021322011321 is 12311022312041.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14021322011321 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14021322010321) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 89582525 + ... + 89738906.
It is an arithmetic number, because the mean of its divisors is an integer number (3505375352736).
Almost surely, 214021322011321 is an apocalyptic number.
It is an amenable number.
14021322011321 is a deficient number, since it is larger than the sum of its proper divisors (179399623).
14021322011321 is an equidigital number, since it uses as much as digits as its factorization.
14021322011321 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 179399622.
The product of its (nonzero) digits is 576, while the sum is 23.
Adding to 14021322011321 its reverse (12311022312041), we get a palindrome (26332344323362).
The spelling of 14021322011321 in words is "fourteen trillion, twenty-one billion, three hundred twenty-two million, eleven thousand, three hundred twenty-one".
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