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14021323201141 is a prime number
BaseRepresentation
bin1100110000001001011111…
…1111010001101001110101
31211122102111010021210201221
43030002113333101221311
53314211132214414031
645453150145150341
72645002313515534
oct314022777215165
954572433253657
1014021323201141
114516456459273
1216a551492b3b1
137a92887cb029
143668c839431b
15194ad7ddda11
hexcc097fd1a75

14021323201141 has 2 divisors, whose sum is σ = 14021323201142. Its totient is φ = 14021323201140.

The previous prime is 14021323201111. The next prime is 14021323201157. The reversal of 14021323201141 is 14110232312041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13992574642225 + 28748558916 = 3740665^2 + 169554^2 .

It is an emirp because it is prime and its reverse (14110232312041) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14021323201141 - 219 = 14021322676853 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14021323201111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7010661600570 + 7010661600571.

It is an arithmetic number, because the mean of its divisors is an integer number (7010661600571).

Almost surely, 214021323201141 is an apocalyptic number.

It is an amenable number.

14021323201141 is a deficient number, since it is larger than the sum of its proper divisors (1).

14021323201141 is an equidigital number, since it uses as much as digits as its factorization.

14021323201141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 14021323201141 its reverse (14110232312041), we get a palindrome (28131555513182).

The spelling of 14021323201141 in words is "fourteen trillion, twenty-one billion, three hundred twenty-three million, two hundred one thousand, one hundred forty-one".