1402133113433 has 8 divisors (see below), whose sum is σ = 1523352247368. Its totient is φ = 1282822942464.

The previous prime is 1402133113399. The next prime is 1402133113471. The reversal of 1402133113433 is 3343113312041.

It can be written as a sum of positive squares in 4 ways, for example, as 20069538889 + 1382063574544 = 141667^2 + 1175612^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1402133113433 - 2⁸ = 1402133113177 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1402133113396 and 1402133113405.

It is not an unprimeable number, because it can be changed into a prime (1402133112433) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 477239210 + ... + 477242147.

It is an arithmetic number, because the mean of its divisors is an integer number (190419030921).

Almost surely, 2^{1402133113433} is an apocalyptic number.

1402133113433 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

1402133113433 is a deficient number, since it is larger than the sum of its proper divisors (121219133935).

1402133113433 is a wasteful number, since it uses less digits than its factorization.

1402133113433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 954481483.

The product of its (nonzero) digits is 7776, while the sum is 29.

Adding to 1402133113433 its reverse (3343113312041), we get a palindrome (4745246425474).

The spelling of 1402133113433 in words is "one trillion, four hundred two billion, one hundred thirty-three million, one hundred thirteen thousand, four hundred thirty-three".