1402133303131 has 4 divisors (see below), whose sum is σ = 1529599967064. Its totient is φ = 1274666639200.

The previous prime is 1402133303119. The next prime is 1402133303159. The reversal of 1402133303131 is 1313033312041.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1402133303131 - 2⁵ = 1402133303099 is a prime.

It is a super-2 number, since 2×1402133303131² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1402133303096 and 1402133303105.

It is not an unprimeable number, because it can be changed into a prime (1402133303161) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 63733331950 + ... + 63733331971.

It is an arithmetic number, because the mean of its divisors is an integer number (382399991766).

Almost surely, 2^{1402133303131} is an apocalyptic number.

1402133303131 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

1402133303131 is a deficient number, since it is larger than the sum of its proper divisors (127466663933).

1402133303131 is a wasteful number, since it uses less digits than its factorization.

1402133303131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 127466663932.

The product of its (nonzero) digits is 1944, while the sum is 25.

Adding to 1402133303131 its reverse (1313033312041), we get a palindrome (2715166615172).

The spelling of 1402133303131 in words is "one trillion, four hundred two billion, one hundred thirty-three million, three hundred three thousand, one hundred thirty-one".