Base | Representation |
---|---|
bin | 11111111000010111110110… |
… | …011001101111001101101111 |
3 | 200101110021010211120111122022 |
4 | 133320113312121233031233 |
5 | 121334223410334220142 |
6 | 1214113041511540355 |
7 | 41351036210423642 |
oct | 3770276631571557 |
9 | 611407124514568 |
10 | 140213341320047 |
11 | 40749164903686 |
12 | 1388635038a6bb |
13 | 60310a4a38998 |
14 | 268a50d1c5a59 |
15 | 113240dd346d2 |
hex | 7f85f666f36f |
140213341320047 has 2 divisors, whose sum is σ = 140213341320048. Its totient is φ = 140213341320046.
The previous prime is 140213341319963. The next prime is 140213341320119. The reversal of 140213341320047 is 740023143312041.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 140213341320047 - 230 = 140212267578223 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 140213341319989 and 140213341320016.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (140213341320347) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70106670660023 + 70106670660024.
It is an arithmetic number, because the mean of its divisors is an integer number (70106670660024).
Almost surely, 2140213341320047 is an apocalyptic number.
140213341320047 is a deficient number, since it is larger than the sum of its proper divisors (1).
140213341320047 is an equidigital number, since it uses as much as digits as its factorization.
140213341320047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48384, while the sum is 35.
Adding to 140213341320047 its reverse (740023143312041), we get a palindrome (880236484632088).
The spelling of 140213341320047 in words is "one hundred forty trillion, two hundred thirteen billion, three hundred forty-one million, three hundred twenty thousand, forty-seven".
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