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14021344410113 is a prime number
BaseRepresentation
bin1100110000001001100101…
…0000001011101000000001
31211122102112121012022222102
43030002121100023220001
53314211203132110423
645453152223520145
72645002662011345
oct314023120135001
954572477168872
1014021344410113
114516467424947
1216a551ba59055
137a9290015811
143668cb115625
15194ad9bccc28
hexcc09940ba01

14021344410113 has 2 divisors, whose sum is σ = 14021344410114. Its totient is φ = 14021344410112.

The previous prime is 14021344410077. The next prime is 14021344410121. The reversal of 14021344410113 is 31101444312041.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 14005647577744 + 15696832369 = 3742412^2 + 125287^2 .

It is a cyclic number.

It is not a de Polignac number, because 14021344410113 - 210 = 14021344409089 is a prime.

It is not a weakly prime, because it can be changed into another prime (14021344410133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7010672205056 + 7010672205057.

It is an arithmetic number, because the mean of its divisors is an integer number (7010672205057).

Almost surely, 214021344410113 is an apocalyptic number.

It is an amenable number.

14021344410113 is a deficient number, since it is larger than the sum of its proper divisors (1).

14021344410113 is an equidigital number, since it uses as much as digits as its factorization.

14021344410113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4608, while the sum is 29.

Adding to 14021344410113 its reverse (31101444312041), we get a palindrome (45122788722154).

The spelling of 14021344410113 in words is "fourteen trillion, twenty-one billion, three hundred forty-four million, four hundred ten thousand, one hundred thirteen".