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140214120402011 = 413419856595171
BaseRepresentation
bin11111111000011000100100…
…110101101100110001011011
3200101110100011010112222011212
4133320120210311230301123
5121334232004310331021
61214113251102213335
741351064420465635
oct3770304465546133
9611410133488155
10140214120402011
1140749524657477
121388652928424b
13603119a276626
14268a584867a55
15113245742885b
hex7f8624d6cc5b

140214120402011 has 4 divisors (see below), whose sum is σ = 143633976997224. Its totient is φ = 136794263806800.

The previous prime is 140214120401981. The next prime is 140214120402017. The reversal of 140214120402011 is 110204021412041.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 140214120402011 - 26 = 140214120401947 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (140214120402017) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1709928297545 + ... + 1709928297626.

It is an arithmetic number, because the mean of its divisors is an integer number (35908494249306).

Almost surely, 2140214120402011 is an apocalyptic number.

140214120402011 is a deficient number, since it is larger than the sum of its proper divisors (3419856595213).

140214120402011 is an equidigital number, since it uses as much as digits as its factorization.

140214120402011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3419856595212.

The product of its (nonzero) digits is 512, while the sum is 23.

Adding to 140214120402011 its reverse (110204021412041), we get a palindrome (250418141814052).

The spelling of 140214120402011 in words is "one hundred forty trillion, two hundred fourteen billion, one hundred twenty million, four hundred two thousand, eleven".

Divisors: 1 41 3419856595171 140214120402011