140214121145113 has 4 divisors (see below), whose sum is σ = 141053726661120. Its totient is φ = 139374515629108.

The previous prime is 140214121145107. The next prime is 140214121145117. The reversal of 140214121145113 is 311541121412041.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 140214121145113 - 2⁵ = 140214121145081 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (140214121145117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 419802757753 + ... + 419802758086.

It is an arithmetic number, because the mean of its divisors is an integer number (35263431665280).

Almost surely, 2^{140214121145113} is an apocalyptic number.

It is an amenable number.

140214121145113 is a deficient number, since it is larger than the sum of its proper divisors (839605516007).

140214121145113 is an equidigital number, since it uses as much as digits as its factorization.

140214121145113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 839605516006.

The product of its (nonzero) digits is 3840, while the sum is 31.

Adding to 140214121145113 its reverse (311541121412041), we get a palindrome (451755242557154).

The spelling of 140214121145113 in words is "one hundred forty trillion, two hundred fourteen billion, one hundred twenty-one million, one hundred forty-five thousand, one hundred thirteen".